Sr Examen

Expresión aornot(b)orcandaand(not(b))andcoraandbandc

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    a∨(¬b)∨(a∧b∧c)∨(a∧c∧(¬b))
    $$a \vee \left(a \wedge b \wedge c\right) \vee \left(a \wedge c \wedge \neg b\right) \vee \neg b$$
    Solución detallada
    $$a \vee \left(a \wedge b \wedge c\right) \vee \left(a \wedge c \wedge \neg b\right) \vee \neg b = a \vee \neg b$$
    Simplificación [src]
    $$a \vee \neg b$$
    a∨(¬b)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$a \vee \neg b$$
    a∨(¬b)
    FNC [src]
    Ya está reducido a FNC
    $$a \vee \neg b$$
    a∨(¬b)
    FNCD [src]
    $$a \vee \neg b$$
    a∨(¬b)
    FNDP [src]
    $$a \vee \neg b$$
    a∨(¬b)