Expresión xv(z∧¬w)v(y∧¬w)v(y∧¬z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
x∨(y∧¬w)∨(y∧¬z)∨(z∧¬w)=x∨(y∧¬z)∨(z∧¬w)
x∨(y∧¬z)∨(z∧¬w)
Tabla de verdad
+---+---+---+---+--------+
| w | x | y | z | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
(x∨y∨z)∧(x∨y∨¬w)∧(x∨z∨¬z)∧(x∨¬w∨¬z)
(x∨y∨z)∧(x∨y∨(¬w))∧(x∨z∨(¬z))∧(x∨(¬w)∨(¬z))
Ya está reducido a FND
x∨(y∧¬z)∨(z∧¬w)
x∨(y∧¬z)∨(z∧¬w)
(x∨y∨z)∧(x∨¬w∨¬z)