Sr Examen
Expresión A∨((B⇒C)∨CA)=0
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Solución
Ha introducido
[src]
¬(a∨(a∧c)∨(b⇒c))
$$\neg \left(a \vee \left(a \wedge c\right) \vee \left(b \Rightarrow c\right)\right)$$
Solución detallada
$$b \Rightarrow c = c \vee \neg b$$
$$a \vee \left(a \wedge c\right) \vee \left(b \Rightarrow c\right) = a \vee c \vee \neg b$$
$$\neg \left(a \vee \left(a \wedge c\right) \vee \left(b \Rightarrow c\right)\right) = b \wedge \neg a \wedge \neg c$$
$$a \vee \left(a \wedge c\right) \vee \left(b \Rightarrow c\right) = a \vee c \vee \neg b$$
$$\neg \left(a \vee \left(a \wedge c\right) \vee \left(b \Rightarrow c\right)\right) = b \wedge \neg a \wedge \neg c$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+