Sr Examen

Expresión ac(!b+d)+a(!b+!c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧(c∨(¬b)))∨(a∧c∧(d∨(¬b)))
    $$\left(a \wedge \left(c \vee \neg b\right)\right) \vee \left(a \wedge c \wedge \left(d \vee \neg b\right)\right)$$
    Solución detallada
    $$\left(a \wedge \left(c \vee \neg b\right)\right) \vee \left(a \wedge c \wedge \left(d \vee \neg b\right)\right) = a \wedge \left(c \vee \neg b\right)$$
    Simplificación [src]
    $$a \wedge \left(c \vee \neg b\right)$$
    a∧(c∨(¬b))
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$a \wedge \left(c \vee \neg b\right)$$
    a∧(c∨(¬b))
    FNCD [src]
    $$a \wedge \left(c \vee \neg b\right)$$
    a∧(c∨(¬b))
    FNDP [src]
    $$\left(a \wedge c\right) \vee \left(a \wedge \neg b\right)$$
    (a∧c)∨(a∧(¬b))
    FND [src]
    $$\left(a \wedge c\right) \vee \left(a \wedge \neg b\right)$$
    (a∧c)∨(a∧(¬b))