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Lógica matemática/ ac∨abc∨a¬b

Expresión ac∨abc∨a¬b

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    Solución

    Ha introducido [src] 
    (a∧c)∨(a∧(¬b))∨(a∧b∧c)
    $$\left(a \wedge c\right) \vee \left(a \wedge \neg b\right) \vee \left(a \wedge b \wedge c\right)$$
    Solución detallada
    $$\left(a \wedge c\right) \vee \left(a \wedge \neg b\right) \vee \left(a \wedge b \wedge c\right) = a \wedge \left(c \vee \neg b\right)$$
    Simplificación [src]
    $$a \wedge \left(c \vee \neg b\right)$$ 
    a∧(c∨(¬b))
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNCD [src]
    $$a \wedge \left(c \vee \neg b\right)$$ 
    a∧(c∨(¬b))
    FNC [src]
    Ya está reducido a FNC
    $$a \wedge \left(c \vee \neg b\right)$$ 
    a∧(c∨(¬b))
    FND [src]
    $$\left(a \wedge c\right) \vee \left(a \wedge \neg b\right)$$ 
    (a∧c)∨(a∧(¬b))
    FNDP [src]
    $$\left(a \wedge c\right) \vee \left(a \wedge \neg b\right)$$ 
    (a∧c)∨(a∧(¬b))
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