Sr Examen
Expresión F=¬(XvY)&(YvX).
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
f⇔((x∨y)∧(¬(x∨y)))
$$f ⇔ \left(\neg \left(x \vee y\right) \wedge \left(x \vee y\right)\right)$$
Solución detallada
$$\neg \left(x \vee y\right) = \neg x \wedge \neg y$$
$$\neg \left(x \vee y\right) \wedge \left(x \vee y\right) = \text{False}$$
$$f ⇔ \left(\neg \left(x \vee y\right) \wedge \left(x \vee y\right)\right) = \neg f$$
$$\neg \left(x \vee y\right) \wedge \left(x \vee y\right) = \text{False}$$
$$f ⇔ \left(\neg \left(x \vee y\right) \wedge \left(x \vee y\right)\right) = \neg f$$
Tabla de verdad
+---+---+---+--------+ | f | x | y | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+