Expresión ab∨a¬b¬c∨¬ab¬c
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Solución
Solución detallada
(a∧b)∨(a∧¬b∧¬c)∨(b∧¬a∧¬c)=(a∧b)∨(a∧¬c)∨(b∧¬c)
(a∧b)∨(a∧¬c)∨(b∧¬c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FND
(a∧b)∨(a∧¬c)∨(b∧¬c)
(a∧b)∨(a∧¬c)∨(b∧¬c)
(a∨b)∧(a∨¬c)∧(b∨¬c)∧(a∨b∨¬c)
(a∨b)∧(a∨(¬c))∧(b∨(¬c))∧(a∨b∨(¬c))
(a∨b)∧(a∨¬c)∧(b∨¬c)