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Lógica matemática/ ab∨a¬b¬c∨¬ab¬c

Expresión ab∨a¬b¬c∨¬ab¬c

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    Solución

    Ha introducido [src] 
    (a∧b)∨(a∧(¬b)∧(¬c))∨(b∧(¬a)∧(¬c))
    $$\left(a \wedge b\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(b \wedge \neg a \wedge \neg c\right)$$
    Solución detallada
    $$\left(a \wedge b\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(b \wedge \neg a \wedge \neg c\right) = \left(a \wedge b\right) \vee \left(a \wedge \neg c\right) \vee \left(b \wedge \neg c\right)$$
    Simplificación [src]
    $$\left(a \wedge b\right) \vee \left(a \wedge \neg c\right) \vee \left(b \wedge \neg c\right)$$ 
    (a∧b)∨(a∧(¬c))∨(b∧(¬c))
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$\left(a \wedge b\right) \vee \left(a \wedge \neg c\right) \vee \left(b \wedge \neg c\right)$$ 
    (a∧b)∨(a∧(¬c))∨(b∧(¬c))
    FNDP [src]
    $$\left(a \wedge b\right) \vee \left(a \wedge \neg c\right) \vee \left(b \wedge \neg c\right)$$ 
    (a∧b)∨(a∧(¬c))∨(b∧(¬c))
    FNC [src]
    $$\left(a \vee b\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg c\right) \wedge \left(a \vee b \vee \neg c\right)$$ 
    (a∨b)∧(a∨(¬c))∧(b∨(¬c))∧(a∨b∨(¬c))
    FNCD [src]
    $$\left(a \vee b\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg c\right)$$ 
    (a∨b)∧(a∨(¬c))∧(b∨(¬c))
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