Expresión (a∧b)∨(b∧c)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∧b)∨(b∧c)=b∧(a∨c)
b∧(a∨c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
b∧(a∨c)
(a∧b)∨(b∧c)
Ya está reducido a FNC
b∧(a∨c)
(a∧b)∨(b∧c)