Expresión xyvy¬zvxzv¬yz
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(x∧y)∨(x∧z)∨(y∧¬z)∨(z∧¬y)=(x∧y)∨(y∧¬z)∨(z∧¬y)
(x∧y)∨(y∧¬z)∨(z∧¬y)
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(x∧y)∨(y∧¬z)∨(z∧¬y)
(y∨z)∧(x∨¬y∨¬z)
(y∨z)∧(y∨¬y)∧(x∨y∨z)∧(x∨y∨¬y)∧(x∨z∨¬z)∧(x∨¬y∨¬z)∧(y∨z∨¬z)∧(y∨¬y∨¬z)
(y∨z)∧(y∨(¬y))∧(x∨y∨z)∧(x∨y∨(¬y))∧(x∨z∨(¬z))∧(y∨z∨(¬z))∧(x∨(¬y)∨(¬z))∧(y∨(¬y)∨(¬z))
Ya está reducido a FND
(x∧y)∨(y∧¬z)∨(z∧¬y)