El profesor se sorprenderá mucho al ver tu solución correcta😉
b∨(¬a)∨(b∧(¬a)∧(¬b))
+---+---+--------+ | a | b | result | +===+===+========+ | 0 | 0 | 1 | +---+---+--------+ | 0 | 1 | 1 | +---+---+--------+ | 1 | 0 | 0 | +---+---+--------+ | 1 | 1 | 1 | +---+---+--------+