Expresión ABC+AB¬C+A¬BC+¬ABC+¬AB¬C
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∧b∧c)∨(a∧b∧¬c)∨(a∧c∧¬b)∨(b∧c∧¬a)∨(b∧¬a∧¬c)=b∨(a∧c)
b∨(a∧c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
b∨(a∧c)
(a∨b)∧(b∨c)
(a∨b)∧(b∨c)
Ya está reducido a FND
b∨(a∧c)