Expresión (xvy)->(x&z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(x \vee y\right) \Rightarrow \left(x \wedge z\right) = \left(x \wedge z\right) \vee \left(\neg x \wedge \neg y\right)$$
$$\left(x \wedge z\right) \vee \left(\neg x \wedge \neg y\right)$$
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(x \vee \neg y\right) \wedge \left(z \vee \neg x\right)$$
Ya está reducido a FND
$$\left(x \wedge z\right) \vee \left(\neg x \wedge \neg y\right)$$
$$\left(x \vee \neg x\right) \wedge \left(x \vee \neg y\right) \wedge \left(z \vee \neg x\right) \wedge \left(z \vee \neg y\right)$$
(x∨(¬x))∧(x∨(¬y))∧(z∨(¬x))∧(z∨(¬y))
$$\left(x \wedge z\right) \vee \left(\neg x \wedge \neg y\right)$$