Sr Examen

Expresión AvC⇔Bv!C

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∨c)⇔(b∨(¬c))
    (ac)(b¬c)\left(a \vee c\right) ⇔ \left(b \vee \neg c\right)
    Solución detallada
    (ac)(b¬c)=(a¬c)(bc)\left(a \vee c\right) ⇔ \left(b \vee \neg c\right) = \left(a \wedge \neg c\right) \vee \left(b \wedge c\right)
    Simplificación [src]
    (a¬c)(bc)\left(a \wedge \neg c\right) \vee \left(b \wedge c\right)
    (b∧c)∨(a∧(¬c))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    (ab)(ac)(b¬c)(c¬c)\left(a \vee b\right) \wedge \left(a \vee c\right) \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg c\right)
    (a∨b)∧(a∨c)∧(b∨(¬c))∧(c∨(¬c))
    FND [src]
    Ya está reducido a FND
    (a¬c)(bc)\left(a \wedge \neg c\right) \vee \left(b \wedge c\right)
    (b∧c)∨(a∧(¬c))
    FNCD [src]
    (ac)(b¬c)\left(a \vee c\right) \wedge \left(b \vee \neg c\right)
    (a∨c)∧(b∨(¬c))
    FNDP [src]
    (a¬c)(bc)\left(a \wedge \neg c\right) \vee \left(b \wedge c\right)
    (b∧c)∨(a∧(¬c))