Expresión AvC⇔Bv!C
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∨c)⇔(b∨¬c)=(a∧¬c)∨(b∧c)
(a∧¬c)∨(b∧c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(a∨b)∧(a∨c)∧(b∨¬c)∧(c∨¬c)
(a∨b)∧(a∨c)∧(b∨(¬c))∧(c∨(¬c))
Ya está reducido a FND
(a∧¬c)∨(b∧c)
(a∨c)∧(b∨¬c)
(a∧¬c)∨(b∧c)