Sr Examen
Lógica matemática/ x&y∨x¬(y)&z∨not(y)&x¬(z)∨x¬(z)

Expresión x&y∨x¬(y)&z∨not(y)&x¬(z)∨x¬(z)

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    (x∧y)∨(x∧(¬z))∨(x∧z∧(¬y))∨(x∧(¬y)∧(¬z))
    (x∧y)∨(x∧¬z)∨(x∧z∧¬y)∨(x∧¬y∧¬z)\left(x \wedge y\right) \vee \left(x \wedge \neg z\right) \vee \left(x \wedge z \wedge \neg y\right) \vee \left(x \wedge \neg y \wedge \neg z\right)
    Solución detallada
    (x∧y)∨(x∧¬z)∨(x∧z∧¬y)∨(x∧¬y∧¬z)=x\left(x \wedge y\right) \vee \left(x \wedge \neg z\right) \vee \left(x \wedge z \wedge \neg y\right) \vee \left(x \wedge \neg y \wedge \neg z\right) = x
    Simplificación [src]
    xx 
    x
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    xx 
    x
    FND [src]
    Ya está reducido a FND
    xx 
    x
    FNDP [src]
    xx 
    x
    FNCD [src]
    xx 
    x
    © Sr Examen – Калькулятор