El profesor se sorprenderá mucho al ver tu solución correcta😉
c∨(d∧(¬c))∨(¬(c∨d))
+---+---+--------+ | c | d | result | +===+===+========+ | 0 | 0 | 1 | +---+---+--------+ | 0 | 1 | 1 | +---+---+--------+ | 1 | 0 | 1 | +---+---+--------+ | 1 | 1 | 1 | +---+---+--------+