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Lógica matemática/ Bv(BvB)^Av(BvC)

Expresión Bv(BvB)^Av(BvC)

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    Solución

    Ha introducido [src] 
    b∨c∨(a∧b)
    $$b \vee c \vee \left(a \wedge b\right)$$
    Solución detallada
    $$b \vee c \vee \left(a \wedge b\right) = b \vee c$$
    Simplificación [src]
    $$b \vee c$$ 
    b∨c
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNCD [src]
    $$b \vee c$$ 
    b∨c
    FNC [src]
    Ya está reducido a FNC
    $$b \vee c$$ 
    b∨c
    FND [src]
    Ya está reducido a FND
    $$b \vee c$$ 
    b∨c
    FNDP [src]
    $$b \vee c$$ 
    b∨c
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