Sr Examen
Factorizar el polinomio z^3+2*z^2+6*z-9
Solución
Ha introducido
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3 2 z + 2*z + 6*z - 9
$$\left(6 z + \left(z^{3} + 2 z^{2}\right)\right) - 9$$
z^3 + 2*z^2 + 6*z - 9
Factorización
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/ ___\ / ___\
| 3 3*I*\/ 3 | | 3 3*I*\/ 3 |
(x - 1)*|x + - + ---------|*|x + - - ---------|
\ 2 2 / \ 2 2 /
$$\left(x - 1\right) \left(x + \left(\frac{3}{2} + \frac{3 \sqrt{3} i}{2}\right)\right) \left(x + \left(\frac{3}{2} - \frac{3 \sqrt{3} i}{2}\right)\right)$$
((x - 1)*(x + 3/2 + 3*i*sqrt(3)/2))*(x + 3/2 - 3*i*sqrt(3)/2)
Simplificación general
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3 2 -9 + z + 2*z + 6*z
$$z^{3} + 2 z^{2} + 6 z - 9$$
-9 + z^3 + 2*z^2 + 6*z
Unión de expresiones racionales
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-9 + z*(6 + z*(2 + z))
$$z \left(z \left(z + 2\right) + 6\right) - 9$$
-9 + z*(6 + z*(2 + z))
Combinatoria
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/ 2 \ (-1 + z)*\9 + z + 3*z/
$$\left(z - 1\right) \left(z^{2} + 3 z + 9\right)$$
(-1 + z)*(9 + z^2 + 3*z)
Parte trigonométrica
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3 2 -9 + z + 2*z + 6*z
$$z^{3} + 2 z^{2} + 6 z - 9$$
-9 + z^3 + 2*z^2 + 6*z
Compilar la expresión
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3 2 -9 + z + 2*z + 6*z
$$z^{3} + 2 z^{2} + 6 z - 9$$
-9 + z^3 + 2*z^2 + 6*z
Denominador racional
[src]
3 2 -9 + z + 2*z + 6*z
$$z^{3} + 2 z^{2} + 6 z - 9$$
-9 + z^3 + 2*z^2 + 6*z