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Solución de sistemas de ecuaciones/ yx=8; x+y+3=0

yx=8; x+y+3=0

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Solución

Ha introducido [src] 
y*x = 8
xy=8x y = 8 
x + y + 3 = 0
(x+y)+3=0\left(x + y\right) + 3 = 0 
x + y + 3 = 0
Respuesta rápida
x1=−32−23i2x_{1} = - \frac{3}{2} - \frac{\sqrt{23} i}{2}
=
−32−23i2- \frac{3}{2} - \frac{\sqrt{23} i}{2}
=
-1.5 - 2.39791576165636*i

y1=−32+23i2y_{1} = - \frac{3}{2} + \frac{\sqrt{23} i}{2}
=
−32+23i2- \frac{3}{2} + \frac{\sqrt{23} i}{2}
=
-1.5 + 2.39791576165636*i
x2=−32+23i2x_{2} = - \frac{3}{2} + \frac{\sqrt{23} i}{2}
=
−32+23i2- \frac{3}{2} + \frac{\sqrt{23} i}{2}
=
-1.5 + 2.39791576165636*i

y2=−32−23i2y_{2} = - \frac{3}{2} - \frac{\sqrt{23} i}{2}
=
−32−23i2- \frac{3}{2} - \frac{\sqrt{23} i}{2}
=
-1.5 - 2.39791576165636*i
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