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xy=1; y=2x²

v

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interior superior

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Solución

Ha introducido [src]
x*y = 1
$$x y = 1$$
       2
y = 2*x 
$$y = 2 x^{2}$$
y = 2*x^2
Respuesta rápida
$$x_{1} = \frac{2^{\frac{2}{3}}}{2}$$
=
$$\frac{2^{\frac{2}{3}}}{2}$$
=
0.793700525984100

$$y_{1} = \sqrt[3]{2}$$
=
$$\sqrt[3]{2}$$
=
1.25992104989487
$$x_{2} = \frac{\left(- \frac{\sqrt[3]{2}}{2} - \frac{\sqrt[3]{2} \sqrt{3} i}{2}\right)^{2}}{2}$$
=
$$\frac{2^{\frac{2}{3}} \left(-1 + \sqrt{3} i\right)}{4}$$
=
-0.39685026299205 + 0.687364818499301*i

$$y_{2} = - \frac{\sqrt[3]{2}}{2} - \frac{\sqrt[3]{2} \sqrt{3} i}{2}$$
=
$$- \frac{\sqrt[3]{2} \left(1 + \sqrt{3} i\right)}{2}$$
=
-0.629960524947437 - 1.09112363597172*i
$$x_{3} = \frac{\left(- \frac{\sqrt[3]{2}}{2} + \frac{\sqrt[3]{2} \sqrt{3} i}{2}\right)^{2}}{2}$$
=
$$\frac{2^{\frac{2}{3}} \left(1 - \sqrt{3} i\right)^{2}}{8}$$
=
-0.39685026299205 - 0.687364818499301*i

$$y_{3} = - \frac{\sqrt[3]{2}}{2} + \frac{\sqrt[3]{2} \sqrt{3} i}{2}$$
=
$$\frac{\sqrt[3]{2} \left(-1 + \sqrt{3} i\right)}{2}$$
=
-0.629960524947437 + 1.09112363597172*i
Respuesta numérica [src]
x1 = 0.7937005259840997
y1 = 1.259921049894873
x1 = 0.7937005259840997
y1 = 1.259921049894873