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Solución de sistemas de ecuaciones/ xy=2; x+y=4

xy=2; x+y=4

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Solución

Ha introducido [src] 
x*y = 2
xy=2x y = 2 
x + y = 4
x+y=4x + y = 4 
x + y = 4
Respuesta rápida
x1=2−2x_{1} = 2 - \sqrt{2}
=
2−22 - \sqrt{2}
=
0.585786437626905

y1=2+2y_{1} = \sqrt{2} + 2
=
2+2\sqrt{2} + 2
=
3.41421356237309
x2=2+2x_{2} = \sqrt{2} + 2
=
2+2\sqrt{2} + 2
=
3.41421356237309

y2=2−2y_{2} = 2 - \sqrt{2}
=
2−22 - \sqrt{2}
=
0.585786437626905
Respuesta numérica [src] 
x1 = 0.585786437626905
y1 = 3.414213562373095
x2 = 3.414213562373095
y2 = 0.585786437626905
x2 = 3.414213562373095
y2 = 0.585786437626905
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