Sr Examen
kx-y+2z=0; 2x+ky-z=3; ky+z=1
Solución
Ha introducido
[src]
k*x - y + 2*z = 0
$$2 z + \left(k x - y\right) = 0$$
2*x + k*y - z = 3
$$- z + \left(k y + 2 x\right) = 3$$
k*y + z = 1
$$k y + z = 1$$
k*y + z = 1
Respuesta rápida
$$k_{1} = -1$$
=
$$-1$$
=
$$x_{1} = z + 1$$
=
$$z + 1$$
=
$$y_{1} = z - 1$$
=
$$z - 1$$
=
=
$$-1$$
=
-1
$$x_{1} = z + 1$$
=
$$z + 1$$
=
1 + z
$$y_{1} = z - 1$$
=
$$z - 1$$
=
-1 + z
$$k_{2} = - \frac{z - 1}{z + 1}$$
=
$$\frac{1 - z}{z + 1}$$
=
$$x_{2} = z + 1$$
=
$$z + 1$$
=
$$y_{2} = z + 1$$
=
$$z + 1$$
=
=
$$\frac{1 - z}{z + 1}$$
=
-(-1 + z)/(1 + z)
$$x_{2} = z + 1$$
=
$$z + 1$$
=
1 + z
$$y_{2} = z + 1$$
=
$$z + 1$$
=
1 + z