Sr Examen
ax=y^2; ay=x^2
Solución
Respuesta rápida
$$a_{1} = y$$
=
$$y$$
=
$$x_{1} = y$$
=
$$y$$
=
=
$$y$$
=
y
$$x_{1} = y$$
=
$$y$$
=
y
$$a_{2} = y \left(- \frac{1}{2} - \frac{\sqrt{3} i}{2}\right)^{2}$$
=
$$\frac{y \left(-1 + \sqrt{3} i\right)}{2}$$
=
$$x_{2} = y \left(- \frac{1}{2} - \frac{\sqrt{3} i}{2}\right)$$
=
$$- \frac{y \left(1 + \sqrt{3} i\right)}{2}$$
=
=
$$\frac{y \left(-1 + \sqrt{3} i\right)}{2}$$
=
y*(-0.5 - 0.866025403784439*i)^2
$$x_{2} = y \left(- \frac{1}{2} - \frac{\sqrt{3} i}{2}\right)$$
=
$$- \frac{y \left(1 + \sqrt{3} i\right)}{2}$$
=
y*(-0.5 - 0.866025403784439*i)
$$a_{3} = y \left(- \frac{1}{2} + \frac{\sqrt{3} i}{2}\right)^{2}$$
=
$$\frac{y \left(1 - \sqrt{3} i\right)^{2}}{4}$$
=
$$x_{3} = y \left(- \frac{1}{2} + \frac{\sqrt{3} i}{2}\right)$$
=
$$\frac{y \left(-1 + \sqrt{3} i\right)}{2}$$
=
=
$$\frac{y \left(1 - \sqrt{3} i\right)^{2}}{4}$$
=
y*(-0.5 + 0.866025403784439*i)^2
$$x_{3} = y \left(- \frac{1}{2} + \frac{\sqrt{3} i}{2}\right)$$
=
$$\frac{y \left(-1 + \sqrt{3} i\right)}{2}$$
=
y*(-0.5 + 0.866025403784439*i)
$$x_{4} = 0$$
=
$$0$$
=
$$y_{4} = 0$$
=
$$0$$
=
=
$$0$$
=
0
$$y_{4} = 0$$
=
$$0$$
=
0