/ x\ \2 / (atan(E))
atan(E)^(2^x)
Sustituimos u=2xu = 2^{x}u=2x.
dduatanu(e)=log(atan(e))atanu(e)\frac{d}{d u} \operatorname{atan}^{u}{\left(e \right)} = \log{\left(\operatorname{atan}{\left(e \right)} \right)} \operatorname{atan}^{u}{\left(e \right)}dudatanu(e)=log(atan(e))atanu(e)
Luego se aplica una cadena de reglas. Multiplicamos por ddx2x\frac{d}{d x} 2^{x}dxd2x:
ddx2x=2xlog(2)\frac{d}{d x} 2^{x} = 2^{x} \log{\left(2 \right)}dxd2x=2xlog(2)
Como resultado de la secuencia de reglas:
2xlog(2)log(atan(e))atan2x(e)2^{x} \log{\left(2 \right)} \log{\left(\operatorname{atan}{\left(e \right)} \right)} \operatorname{atan}^{2^{x}}{\left(e \right)}2xlog(2)log(atan(e))atan2x(e)
Respuesta:
/ x\ x \2 / 2 *(atan(E)) *log(2)*log(atan(E))
/ x\ x \2 / 2 / x \ 2 *(atan(E)) *log (2)*\1 + 2 *log(atan(E))/*log(atan(E))
/ x\ x \2 / 3 / 2*x 2 x \ 2 *(atan(E)) *log (2)*\1 + 2 *log (atan(E)) + 3*2 *log(atan(E))/*log(atan(E))