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Ecuación diferencial y''''+5y''+4y=sinx*cosx

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
             2           4                      
            d           d                       
4*y(x) + 5*---(y(x)) + ---(y(x)) = cos(x)*sin(x)
             2           4                      
           dx          dx                       
$$4 y{\left(x \right)} + 5 \frac{d^{2}}{d x^{2}} y{\left(x \right)} + \frac{d^{4}}{d x^{4}} y{\left(x \right)} = \sin{\left(x \right)} \cos{\left(x \right)}$$
4*y + 5*y'' + y'''' = sin(x)*cos(x)
Respuesta [src]
                                             /     x \         
y(x) = C2*sin(x) + C3*sin(2*x) + C4*cos(x) + |C1 + --|*cos(2*x)
                                             \     24/         
$$y{\left(x \right)} = C_{2} \sin{\left(x \right)} + C_{3} \sin{\left(2 x \right)} + C_{4} \cos{\left(x \right)} + \left(C_{1} + \frac{x}{24}\right) \cos{\left(2 x \right)}$$
Clasificación
nth linear constant coeff variation of parameters
nth linear constant coeff variation of parameters Integral