Ecuación diferencial (sinysiny+xctgy)*y'=1

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

Ha introducido [src]

/   2                    \ d           
\sin (y(x)) + x*cot(y(x))/*--(y(x)) = 1
                           dx

$$\left(x \cot{\left(y{\left(x \right)} \right)} + \sin^{2}{\left(y{\left(x \right)} \right)}\right) \frac{d}{d x} y{\left(x \right)} = 1$$

(x*cot(y) + sin(y)^2)*y' = 1

Gráfico para el problema de Cauchy

Clasificación

1st exact

1st power series

lie group

1st exact Integral

Respuesta numérica [src]

(x, y):

(-10.0, 0.75)

(-7.777777777777778, 0.5537762116567145)

(-5.555555555555555, 0.38299384822428384)

(-3.333333333333333, 0.22541464767013247)

(-1.1111111111111107, 0.07445992674636945)

(1.1111111111111107, -0.07445977738114207)

(3.333333333333334, -0.22541421455889812)

(5.555555555555557, -0.3829931102693094)

(7.777777777777779, -0.5537750769950246)

(10.0, -0.7499984014197795)

(10.0, -0.7499984014197795)

Ecuación diferencial (siny*siny+x*ctgy)*y'=1