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Ecuación diferencial y'-2*x*y-y^2=5-x^2

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
   2                 d               2
- y (x) - 2*x*y(x) + --(y(x)) = 5 - x 
                     dx               
$$- 2 x y{\left(x \right)} - y^{2}{\left(x \right)} + \frac{d}{d x} y{\left(x \right)} = 5 - x^{2}$$
-2*x*y - y^2 + y' = 5 - x^2
Respuesta [src]
                           3 /        2     /      2\ /      2\\    5 /         2   /      2\ /         2\   /      2\ /         2     /        2\ /      2\       2 /      2\\       2 /      2\\                         4 /         2     /      2\ /      2\\        
              /      2\   x *\4 + 3*C1  + 3*\2 + C1 /*\5 + C1 //   x *\-2 + 5*C1  + \5 + C1 /*\11 + 9*C1 / + \5 + C1 /*\11 + 9*C1  + 3*\4 + 3*C1 /*\5 + C1 / + 6*C1 *\4 + C1 // + 6*C1 *\4 + C1 //       2 /      2\   C1*x *\11 + 3*C1  + 3*\4 + C1 /*\5 + C1 //    / 6\
y(x) = C1 + x*\5 + C1 / + -------------------------------------- + ------------------------------------------------------------------------------------------------------------------------------- + C1*x *\6 + C1 / + ------------------------------------------ + O\x /
                                            3                                                                                     15                                                                                                       3                             
$$y{\left(x \right)} = x \left(C_{1}^{2} + 5\right) + \frac{x^{3} \left(3 C_{1}^{2} + 3 \left(C_{1}^{2} + 2\right) \left(C_{1}^{2} + 5\right) + 4\right)}{3} + \frac{x^{5} \left(6 C_{1}^{2} \left(C_{1}^{2} + 4\right) + 5 C_{1}^{2} + \left(C_{1}^{2} + 5\right) \left(9 C_{1}^{2} + 11\right) + \left(C_{1}^{2} + 5\right) \left(6 C_{1}^{2} \left(C_{1}^{2} + 4\right) + 9 C_{1}^{2} + 3 \left(C_{1}^{2} + 5\right) \left(3 C_{1}^{2} + 4\right) + 11\right) - 2\right)}{15} + C_{1} + C_{1} x^{2} \left(C_{1}^{2} + 6\right) + \frac{C_{1} x^{4} \left(3 C_{1}^{2} + 3 \left(C_{1}^{2} + 4\right) \left(C_{1}^{2} + 5\right) + 11\right)}{3} + O\left(x^{6}\right)$$
Gráfico para el problema de Cauchy
Clasificación
1st power series
lie group
Respuesta numérica [src]
(x, y):
(-10.0, 0.75)
(-7.777777777777778, -3.0124475225741065)
(-5.555555555555555, -2.007265775624695)
(-3.333333333333333, -0.884620112761744)
(-1.1111111111111107, 1.285180573443081)
(1.1111111111111107, 9151477.390604295)
(3.333333333333334, 3.1933833808213433e-248)
(5.555555555555557, 1.7159818507571235e+185)
(7.777777777777779, 8.388243571811809e+296)
(10.0, 3.861029683e-315)
(10.0, 3.861029683e-315)