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Ecuación diferencial y''-15y'+36y=-6e^(3x)-2cos(2x)

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
                            2                              
     d                     d               3*x             
- 15*--(y(x)) + 36*y(x) + ---(y(x)) = - 6*e    - 2*cos(2*x)
     dx                     2                              
                          dx                               
$$36 y{\left(x \right)} - 15 \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = - 6 e^{3 x} - 2 \cos{\left(2 x \right)}$$
36*y - 15*y' + y'' = -6*exp(3*x) - 2*cos(2*x)
Respuesta [src]
         16*cos(2*x)   15*sin(2*x)       12*x   /     2*x\  3*x
y(x) = - ----------- + ----------- + C2*e     + |C1 + ---|*e   
             481           481                  \      3 /     
$$y{\left(x \right)} = C_{2} e^{12 x} + \left(C_{1} + \frac{2 x}{3}\right) e^{3 x} + \frac{15 \sin{\left(2 x \right)}}{481} - \frac{16 \cos{\left(2 x \right)}}{481}$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth linear constant coeff variation of parameters Integral