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Ecuación diferencial y''-8y'+25y=5x^2-e^-x-7e^-x

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
                           2                       
    d                     d               -x      2
- 8*--(y(x)) + 25*y(x) + ---(y(x)) = - 8*e   + 5*x 
    dx                     2                       
                         dx                        
$$25 y{\left(x \right)} - 8 \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = 5 x^{2} - 8 e^{- x}$$
25*y - 8*y' + y'' = 5*x^2 - 8*exp(-x)
Respuesta [src]
                 -x    2                                          
        78    4*e     x    16*x                                4*x
y(x) = ---- - ----- + -- + ---- + (C1*sin(3*x) + C2*cos(3*x))*e   
       3125     17    5    125                                    
$$y{\left(x \right)} = \frac{x^{2}}{5} + \frac{16 x}{125} + \left(C_{1} \sin{\left(3 x \right)} + C_{2} \cos{\left(3 x \right)}\right) e^{4 x} + \frac{78}{3125} - \frac{4 e^{- x}}{17}$$
Clasificación
nth linear constant coeff undetermined coefficients
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nth linear constant coeff variation of parameters Integral