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Ecuación diferencial y''+2*y'+5*y=(e^(2*x))*(x^2-7*x+2)

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
                        2                            
  d                    d          /     2      \  2*x
2*--(y(x)) + 5*y(x) + ---(y(x)) = \2 + x  - 7*x/*e   
  dx                    2                            
                      dx                             
$$5 y{\left(x \right)} + 2 \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = \left(x^{2} - 7 x + 2\right) e^{2 x}$$
5*y + 2*y' + y'' = (x^2 - 7*x + 2)*exp(2*x)
Respuesta [src]
                                         /                    2\  2*x
                                    -x   \930 - 1339*x + 169*x /*e   
y(x) = (C1*sin(2*x) + C2*cos(2*x))*e   + ----------------------------
                                                     2197            
$$y{\left(x \right)} = \left(C_{1} \sin{\left(2 x \right)} + C_{2} \cos{\left(2 x \right)}\right) e^{- x} + \frac{\left(169 x^{2} - 1339 x + 930\right) e^{2 x}}{2197}$$
Clasificación
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