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Ecuación diferencial dx*(2*x^2*y+6*y^3)=5*dy*x^4*y^2

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v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
   3         2           4  2    d       
6*y (x) + 2*x *y(x) = 5*x *y (x)*--(y(x))
                                 dx      
$$2 x^{2} y{\left(x \right)} + 6 y^{3}{\left(x \right)} = 5 x^{4} y^{2}{\left(x \right)} \frac{d}{d x} y{\left(x \right)}$$
2*x^2*y + 6*y^3 = 5*x^4*y^2*y'
Respuesta [src]
y(x) = 0
$$y{\left(x \right)} = 0$$
                       ______________________________________________________ 
                      /                                                 -4    
                     /                                                  ----  
                    /   /                              /        pi*I\\     3  
          ____     /    |         2/3 3 ____           |     4*e    ||  5*x   
       -\/ 30 *   /     |C1 + (-1)   *\/ 10 *lowergamma|1/3, -------||*e      
                 /      |                              |          3 ||        
               \/       \                              \       5*x  //        
y(x) = -----------------------------------------------------------------------
                                          15                                  
$$y{\left(x \right)} = - \frac{\sqrt{30} \sqrt{\left(C_{1} + \left(-1\right)^{\frac{2}{3}} \sqrt[3]{10} \gamma\left(\frac{1}{3}, \frac{4 e^{i \pi}}{5 x^{3}}\right)\right) e^{- \frac{4}{5 x^{3}}}}}{15}$$
                      ______________________________________________________
                     /                                                 -4   
                    /                                                  ---- 
                   /   /                              /        pi*I\\     3 
         ____     /    |         2/3 3 ____           |     4*e    ||  5*x  
       \/ 30 *   /     |C1 + (-1)   *\/ 10 *lowergamma|1/3, -------||*e     
                /      |                              |          3 ||       
              \/       \                              \       5*x  //       
y(x) = ---------------------------------------------------------------------
                                         15                                 
$$y{\left(x \right)} = \frac{\sqrt{30} \sqrt{\left(C_{1} + \left(-1\right)^{\frac{2}{3}} \sqrt[3]{10} \gamma\left(\frac{1}{3}, \frac{4 e^{i \pi}}{5 x^{3}}\right)\right) e^{- \frac{4}{5 x^{3}}}}}{15}$$
Clasificación
factorable
Bernoulli
lie group
Bernoulli Integral