Sr Examen

Ecuación diferencial xy''=y'(ln(y'/x))-y'

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
                                       /d       \
    2                                  |--(y(x))|
   d            d          d           |dx      |
x*---(y(x)) = - --(y(x)) + --(y(x))*log|--------|
    2           dx         dx          \   x    /
  dx                                             
$$x \frac{d^{2}}{d x^{2}} y{\left(x \right)} = \log{\left(\frac{\frac{d}{d x} y{\left(x \right)}}{x} \right)} \frac{d}{d x} y{\left(x \right)} - \frac{d}{d x} y{\left(x \right)}$$
x*y'' = log(y'/x)*y' - y'
Respuesta [src]
            //             2 + C1*x              \
            ||(-1 + C1*x)*e                2     |
            ||---------------------  for C1  != 0|
            ||           2                       |
            ||         C1                        |
y(x) = C1 + |<                                   |
            ||          2                        |
            ||         x                         |
            ||         --             otherwise  |
            ||         2                         |
            \\                                   /
$$y{\left(x \right)} = C_{1} + \begin{cases} \frac{\left(C_{1} x - 1\right) e^{C_{1} x + 2}}{C_{1}^{2}} & \text{for}\: C_{1}^{2} \neq 0 \\\frac{x^{2}}{2} & \text{otherwise} \end{cases}$$
Clasificación
nth order reducible