Sr Examen

Ecuación diferencial yy'cos²y-sinx=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
             2       d                
-sin(x) + cos (y(x))*--(y(x))*y(x) = 0
                     dx               
$$y{\left(x \right)} \cos^{2}{\left(y{\left(x \right)} \right)} \frac{d}{d x} y{\left(x \right)} - \sin{\left(x \right)} = 0$$
y*cos(y)^2*y' - sin(x) = 0
Respuesta [src]
     2            2        2         2        2                                            
  sin (y(x))   cos (y(x))*y (x)   sin (y(x))*y (x)   cos(y(x))*sin(y(x))*y(x)              
- ---------- + ---------------- + ---------------- + ------------------------ + cos(x) = C1
      4               4                  4                      2                          
$$\frac{y^{2}{\left(x \right)} \sin^{2}{\left(y{\left(x \right)} \right)}}{4} + \frac{y^{2}{\left(x \right)} \cos^{2}{\left(y{\left(x \right)} \right)}}{4} + \frac{y{\left(x \right)} \sin{\left(y{\left(x \right)} \right)} \cos{\left(y{\left(x \right)} \right)}}{2} - \frac{\sin^{2}{\left(y{\left(x \right)} \right)}}{4} + \cos{\left(x \right)} = C_{1}$$
Gráfico para el problema de Cauchy
Clasificación
separable
1st exact
1st power series
lie group
separable Integral
1st exact Integral
Respuesta numérica [src]
(x, y):
(-10.0, 0.75)
(-7.777777777777778, 1.6031717505649392)
(-5.555555555555555, 2.17e-322)
(-3.333333333333333, nan)
(-1.1111111111111107, 2.78363573e-315)
(1.1111111111111107, 6.971028255580836e+173)
(3.333333333333334, 3.1933833808213398e-248)
(5.555555555555557, 5.107659831618641e-38)
(7.777777777777779, 8.388243567735152e+296)
(10.0, 3.4850068345956685e-196)
(10.0, 3.4850068345956685e-196)