Sr Examen

Ecuación diferencial xy'''=y''-xy'

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
    3                          2      
   d              d           d       
x*---(y(x)) = - x*--(y(x)) + ---(y(x))
    3             dx           2      
  dx                         dx       
$$x \frac{d^{3}}{d x^{3}} y{\left(x \right)} = - x \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)}$$
x*y''' = -x*y' + y''
Respuesta [src]
                                                                         
                       /               |  2\           _  /       |   2 \
                __2, 1 |   1       0   | x |       3  |_  | 3/2   | -x  |
y(x) = C1 + C3*/__     |               | --| + C2*x * |   |       | ----|
               \_|2, 4 \3/2, 1/2  0, 0 | 4 /         1  2 \2, 5/2 |  4  /
$$y{\left(x \right)} = C_{1} + C_{2} x^{3} {{}_{1}F_{2}\left(\begin{matrix} \frac{3}{2} \\ 2, \frac{5}{2} \end{matrix}\middle| {- \frac{x^{2}}{4}} \right)} + C_{3} {G_{2, 4}^{2, 1}\left(\begin{matrix} 1 & 0 \\\frac{3}{2}, \frac{1}{2} & 0, 0 \end{matrix} \middle| {\frac{x^{2}}{4}} \right)}$$
Clasificación
nth order reducible