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Ecuación diferencial y'''-4y''+3y'=o

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
      2                        3          
     d            d           d           
- 4*---(y(x)) + 3*--(y(x)) + ---(y(x)) = o
      2           dx           3          
    dx                       dx           
$$3 \frac{d}{d x} y{\left(x \right)} - 4 \frac{d^{2}}{d x^{2}} y{\left(x \right)} + \frac{d^{3}}{d x^{3}} y{\left(x \right)} = o$$
3*y' - 4*y'' + y''' = o
Respuesta [src]
                x       3*x   o*x
y(x) = C1 + C2*e  + C3*e    + ---
                               3 
$$y{\left(x \right)} = C_{1} + C_{2} e^{x} + C_{3} e^{3 x} + \frac{o x}{3}$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth order reducible
nth linear constant coeff variation of parameters Integral