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Ecuación diferencial y''''-y''=3x²+4sen(x)-2cos(x)

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
    2           4                                    
   d           d                         2           
- ---(y(x)) + ---(y(x)) = -2*cos(x) + 3*x  + 4*sin(x)
    2           4                                    
  dx          dx                                     
$$- \frac{d^{2}}{d x^{2}} y{\left(x \right)} + \frac{d^{4}}{d x^{4}} y{\left(x \right)} = 3 x^{2} + 4 \sin{\left(x \right)} - 2 \cos{\left(x \right)}$$
-y'' + y'''' = 3*x^2 + 4*sin(x) - 2*cos(x)
Respuesta [src]
                                        4                        
                        2              x               -x       x
y(x) = C1 - cos(x) - 3*x  + 2*sin(x) - -- + C2*x + C3*e   + C4*e 
                                       4                         
$$y{\left(x \right)} = C_{1} + C_{2} x + C_{3} e^{- x} + C_{4} e^{x} - \frac{x^{4}}{4} - 3 x^{2} + 2 \sin{\left(x \right)} - \cos{\left(x \right)}$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth order reducible
nth linear constant coeff variation of parameters Integral