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Ecuación diferencial 2𝑦''+3y'+2y=14x^2-4x-11

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
    2                                                
   d                     d                          2
2*---(y(x)) + 2*y(x) + 3*--(y(x)) = -11 - 4*x + 14*x 
    2                    dx                          
  dx                                                 
$$2 y{\left(x \right)} + 3 \frac{d}{d x} y{\left(x \right)} + 2 \frac{d^{2}}{d x^{2}} y{\left(x \right)} = 14 x^{2} - 4 x - 11$$
2*y + 3*y' + 2*y'' = 14*x^2 - 4*x - 11
Respuesta [src]
                                                               -3*x
                          /      /    ___\         /    ___\\  ----
                      2   |      |x*\/ 7 |         |x*\/ 7 ||   4  
y(x) = 15 - 23*x + 7*x  + |C1*sin|-------| + C2*cos|-------||*e    
                          \      \   4   /         \   4   //      
$$y{\left(x \right)} = 7 x^{2} - 23 x + \left(C_{1} \sin{\left(\frac{\sqrt{7} x}{4} \right)} + C_{2} \cos{\left(\frac{\sqrt{7} x}{4} \right)}\right) e^{- \frac{3 x}{4}} + 15$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth linear constant coeff variation of parameters Integral