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Ecuación diferencial y'''-4y''+3y'=-9(x^2)+6x+9

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
      2                        3                       
     d            d           d                 2      
- 4*---(y(x)) + 3*--(y(x)) + ---(y(x)) = 9 - 9*x  + 6*x
      2           dx           3                       
    dx                       dx                        
$$3 \frac{d}{d x} y{\left(x \right)} - 4 \frac{d^{2}}{d x^{2}} y{\left(x \right)} + \frac{d^{3}}{d x^{3}} y{\left(x \right)} = - 9 x^{2} + 6 x + 9$$
3*y' - 4*y'' + y''' = -9*x^2 + 6*x + 9
Respuesta [src]
             3            2       x       3*x
y(x) = C1 - x  - 3*x - 3*x  + C2*e  + C3*e   
$$y{\left(x \right)} = C_{1} + C_{2} e^{x} + C_{3} e^{3 x} - x^{3} - 3 x^{2} - 3 x$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth order reducible
nth linear constant coeff variation of parameters Integral