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Ecuación diferencial y''''+2y'''+2y''+2y'+y=x*e^x

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
                 2             3           4                    
  d             d             d           d                    x
2*--(y(x)) + 2*---(y(x)) + 2*---(y(x)) + ---(y(x)) + y(x) = x*e 
  dx             2             3           4                    
               dx            dx          dx                     
$$y{\left(x \right)} + 2 \frac{d}{d x} y{\left(x \right)} + 2 \frac{d^{2}}{d x^{2}} y{\left(x \right)} + 2 \frac{d^{3}}{d x^{3}} y{\left(x \right)} + \frac{d^{4}}{d x^{4}} y{\left(x \right)} = x e^{x}$$
y + 2*y' + 2*y'' + 2*y''' + y'''' = x*exp(x)
Respuesta [src]
                                                           x
                                            -x   (-2 + x)*e 
y(x) = C3*sin(x) + C4*cos(x) + (C1 + C2*x)*e   + -----------
                                                      8     
$$y{\left(x \right)} = C_{3} \sin{\left(x \right)} + C_{4} \cos{\left(x \right)} + \left(C_{1} + C_{2} x\right) e^{- x} + \frac{\left(x - 2\right) e^{x}}{8}$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth linear constant coeff variation of parameters Integral