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Ecuación diferencial cos^2ydx-tgxdy=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
   2         d                  
cos (y(x)) - --(y(x))*tan(x) = 0
             dx                 
$$\cos^{2}{\left(y{\left(x \right)} \right)} - \tan{\left(x \right)} \frac{d}{d x} y{\left(x \right)} = 0$$
cos(y)^2 - tan(x)*y' = 0
Respuesta [src]
             /        ___________________________________________\
             |       /       2      2                            |
             |-1 + \/  1 + C1  + log (sin(x)) + 2*C1*log(sin(x)) |
y(x) = 2*atan|---------------------------------------------------|
             \                  C1 + log(sin(x))                 /
$$y{\left(x \right)} = 2 \operatorname{atan}{\left(\frac{\sqrt{C_{1}^{2} + 2 C_{1} \log{\left(\sin{\left(x \right)} \right)} + \log{\left(\sin{\left(x \right)} \right)}^{2} + 1} - 1}{C_{1} + \log{\left(\sin{\left(x \right)} \right)}} \right)}$$
              /       ___________________________________________\
              |      /       2      2                            |
              |1 + \/  1 + C1  + log (sin(x)) + 2*C1*log(sin(x)) |
y(x) = -2*atan|--------------------------------------------------|
              \                 C1 + log(sin(x))                 /
$$y{\left(x \right)} = - 2 \operatorname{atan}{\left(\frac{\sqrt{C_{1}^{2} + 2 C_{1} \log{\left(\sin{\left(x \right)} \right)} + \log{\left(\sin{\left(x \right)} \right)}^{2} + 1} + 1}{C_{1} + \log{\left(\sin{\left(x \right)} \right)}} \right)}$$
Clasificación
factorable
separable
lie group
separable Integral