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- La ecuación:
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Ecuación 6*x^2+x-7=0
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Ecuación 2-5(3+2x)=17
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Ecuación (6*x+8)/2+5=5*x/3
- Expresar {x} en función de y en la ecuación:
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Expresiones idénticas
- dos -log tres (x+ siete)=log(uno ÷3)(dos ×x)
- 2 menos logaritmo de 3(x más 7) es igual a logaritmo de (1÷3)(2×x)
- dos menos logaritmo de tres (x más siete) es igual a logaritmo de (uno ÷3)(dos ×x)
- 2-log3x+7=log1÷32×x
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Expresiones semejantes
- 2+log3(x+7)=log(1÷3)(2×x)
- 2-log3(x-7)=log(1÷3)(2×x)
-
Expresiones con funciones
- Logaritmo log
- log(c)=0
- Log[2,34-2^x]=2-Sqrt[x-4]=0
- log2x-5log2x=0
- log(y)=-sin(x)
- log(3*x)=2-x
2-log3(x+7)=log(1÷3)(2×x) la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Ha introducido
[src]
log(x + 7)
2 - ---------- = log(1/3)*2*x
log(3)
$$- \frac{\log{\left(x + 7 \right)}}{\log{\left(3 \right)}} + 2 = 2 x \log{\left(\frac{1}{3} \right)}$$
Suma y producto de raíces
[src]
suma
/ 2 \ / 2 \
| 2 -14*log (3)| | 2 -14*log (3) |
W\-18*log (3)*e / W\-18*log (3)*e , -1/
-7 - --------------------------- + -7 - -------------------------------
2 2
2*log (3) 2*log (3)
$$\left(-7 - \frac{W\left(- \frac{18 \log{\left(3 \right)}^{2}}{e^{14 \log{\left(3 \right)}^{2}}}\right)}{2 \log{\left(3 \right)}^{2}}\right) + \left(-7 - \frac{W_{-1}\left(- \frac{18 \log{\left(3 \right)}^{2}}{e^{14 \log{\left(3 \right)}^{2}}}\right)}{2 \log{\left(3 \right)}^{2}}\right)$$
=
/ 2 \ / 2 \
| 2 -14*log (3)| | 2 -14*log (3) |
W\-18*log (3)*e / W\-18*log (3)*e , -1/
-14 - --------------------------- - -------------------------------
2 2
2*log (3) 2*log (3)
$$-14 - \frac{W\left(- \frac{18 \log{\left(3 \right)}^{2}}{e^{14 \log{\left(3 \right)}^{2}}}\right)}{2 \log{\left(3 \right)}^{2}} - \frac{W_{-1}\left(- \frac{18 \log{\left(3 \right)}^{2}}{e^{14 \log{\left(3 \right)}^{2}}}\right)}{2 \log{\left(3 \right)}^{2}}$$
producto
/ / 2 \\ / / 2 \\ | | 2 -14*log (3)|| | | 2 -14*log (3) || | W\-18*log (3)*e /| | W\-18*log (3)*e , -1/| |-7 - ---------------------------|*|-7 - -------------------------------| | 2 | | 2 | \ 2*log (3) / \ 2*log (3) /
$$\left(-7 - \frac{W\left(- \frac{18 \log{\left(3 \right)}^{2}}{e^{14 \log{\left(3 \right)}^{2}}}\right)}{2 \log{\left(3 \right)}^{2}}\right) \left(-7 - \frac{W_{-1}\left(- \frac{18 \log{\left(3 \right)}^{2}}{e^{14 \log{\left(3 \right)}^{2}}}\right)}{2 \log{\left(3 \right)}^{2}}\right)$$
=
/ / 2 \\ / / 2 \\
| 2 | 2 -14*log (3)|| | 2 | 2 -14*log (3) ||
\14*log (3) + W\-18*log (3)*e //*\14*log (3) + W\-18*log (3)*e , -1//
-----------------------------------------------------------------------------------------
4
4*log (3)
$$\frac{\left(W\left(- \frac{18 \log{\left(3 \right)}^{2}}{e^{14 \log{\left(3 \right)}^{2}}}\right) + 14 \log{\left(3 \right)}^{2}\right) \left(W_{-1}\left(- \frac{18 \log{\left(3 \right)}^{2}}{e^{14 \log{\left(3 \right)}^{2}}}\right) + 14 \log{\left(3 \right)}^{2}\right)}{4 \log{\left(3 \right)}^{4}}$$
(14*log(3)^2 + LambertW(-18*log(3)^2*exp(-14*log(3)^2)))*(14*log(3)^2 + LambertW(-18*log(3)^2*exp(-14*log(3)^2), -1))/(4*log(3)^4)
Respuesta rápida
[src]
/ 2 \
| 2 -14*log (3)|
W\-18*log (3)*e /
x1 = -7 - ---------------------------
2
2*log (3)
$$x_{1} = -7 - \frac{W\left(- \frac{18 \log{\left(3 \right)}^{2}}{e^{14 \log{\left(3 \right)}^{2}}}\right)}{2 \log{\left(3 \right)}^{2}}$$
/ 2 \
| 2 -14*log (3) |
W\-18*log (3)*e , -1/
x2 = -7 - -------------------------------
2
2*log (3)
$$x_{2} = -7 - \frac{W_{-1}\left(- \frac{18 \log{\left(3 \right)}^{2}}{e^{14 \log{\left(3 \right)}^{2}}}\right)}{2 \log{\left(3 \right)}^{2}}$$
x2 = -7 - LambertW(-18*exp(-14*log(3)^2)*log(3^2, -1)/(2*log(3)^2))