z=arcctg(x-y) la ecuación

El profesor se sorprenderá mucho al ver tu solución correcta😉

Ha introducido [src]

z = acot(x - y)

z = \operatorname{acot}{\left(x - y \right)}

Simplificar

Gráfica

Respuesta rápida [src]

z1 = I*im(acot(x - y)) + re(acot(x - y))

z_{1} = \operatorname{re}{\left(\operatorname{acot}{\left(x - y \right)}\right)} + i \operatorname{im}{\left(\operatorname{acot}{\left(x - y \right)}\right)}

z1 = re(acot(x - y)) + i*im(acot(x - y))

Suma y producto de raíces [src]

suma

I*im(acot(x - y)) + re(acot(x - y))

\operatorname{re}{\left(\operatorname{acot}{\left(x - y \right)}\right)} + i \operatorname{im}{\left(\operatorname{acot}{\left(x - y \right)}\right)}

I*im(acot(x - y)) + re(acot(x - y))

\operatorname{re}{\left(\operatorname{acot}{\left(x - y \right)}\right)} + i \operatorname{im}{\left(\operatorname{acot}{\left(x - y \right)}\right)}

producto

I*im(acot(x - y)) + re(acot(x - y))

\operatorname{re}{\left(\operatorname{acot}{\left(x - y \right)}\right)} + i \operatorname{im}{\left(\operatorname{acot}{\left(x - y \right)}\right)}

I*im(acot(x - y)) + re(acot(x - y))

\operatorname{re}{\left(\operatorname{acot}{\left(x - y \right)}\right)} + i \operatorname{im}{\left(\operatorname{acot}{\left(x - y \right)}\right)}

i*im(acot(x - y)) + re(acot(x - y))