Cx-1^x*(x-1)=30 la ecuación
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Solución
Resolución de la ecuación paramétrica
Se da la ecuación con parámetro:
cx−x+1=30Коэффициент при x равен
c−1entonces son posibles los casos para c :
c<1c=1Consideremos todos los casos con detalles:
Con
c<1la ecuación será
−x−29=0su solución
x=−29Con
c=1la ecuación será
−29=0su solución
no hay soluciones
29*(-1 + re(c)) 29*I*im(c)
x1 = ---------------------- - ----------------------
2 2 2 2
(-1 + re(c)) + im (c) (-1 + re(c)) + im (c)
x1=(re(c)−1)2+(im(c))229(re(c)−1)−(re(c)−1)2+(im(c))229iim(c)
x1 = 29*(re(c) - 1)/((re(c) - 1)^2 + im(c)^2) - 29*i*im(c)/((re(c) - 1)^2 + im(c)^2)
Suma y producto de raíces
[src]
29*(-1 + re(c)) 29*I*im(c)
---------------------- - ----------------------
2 2 2 2
(-1 + re(c)) + im (c) (-1 + re(c)) + im (c)
(re(c)−1)2+(im(c))229(re(c)−1)−(re(c)−1)2+(im(c))229iim(c)
29*(-1 + re(c)) 29*I*im(c)
---------------------- - ----------------------
2 2 2 2
(-1 + re(c)) + im (c) (-1 + re(c)) + im (c)
(re(c)−1)2+(im(c))229(re(c)−1)−(re(c)−1)2+(im(c))229iim(c)
29*(-1 + re(c)) 29*I*im(c)
---------------------- - ----------------------
2 2 2 2
(-1 + re(c)) + im (c) (-1 + re(c)) + im (c)
(re(c)−1)2+(im(c))229(re(c)−1)−(re(c)−1)2+(im(c))229iim(c)
29*(-1 - I*im(c) + re(c))
-------------------------
2 2
(-1 + re(c)) + im (c)
(re(c)−1)2+(im(c))229(re(c)−iim(c)−1)
29*(-1 - i*im(c) + re(c))/((-1 + re(c))^2 + im(c)^2)