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- La ecuación:
-
Ecuación (x-3)*(x+2)=0
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Ecuación (11x+14)-(5x-8)=25
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Ecuación z^2-6*z+10=0
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Ecuación 4/(x-4)=-5
- Expresar {x} en función de y en la ecuación:
- -7*x-13*y=5
- 15*x+1*y=19
- 7*x-1*y=-7
- -11*x-14*y=-3
- Integral de d{x}:
- tgx
- Gráfico de la función y =:
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tgx
- Derivada de:
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tgx
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Expresiones idénticas
- arcctgx*arccosx1/ cinco +arcctgx1/ cuarenta y cinco =tgx
- arcctgx multiplicar por arc coseno de x1 dividir por 5 más arcctgx1 dividir por 45 es igual a tgx
- arcctgx multiplicar por arc coseno de x1 dividir por cinco más arcctgx1 dividir por cuarenta y cinco es igual a tgx
- arcctgxarccosx1/5+arcctgx1/45=tgx
- arcctgx*arccosx1 dividir por 5+arcctgx1 dividir por 45=tgx
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Expresiones semejantes
- tg(x)=-1
- arcctgx*arccosx1/5-arcctgx1/45=tgx
- tg(x)=-2
- tg(x)=-sqrt(3)/3
- tg(x)=3
- tg(x)=-1/2
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Expresiones con funciones
- arcctgx
- arcctgxx=-2/3
- tgx
- tgx-x=.0001
- tgx-x=0.251
- tgx=3x+5y
- tgx=-7.8
- tgx=-(3/4)
arcctgx*arccosx1/5+arcctgx1/45=tgx la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Ha introducido
[src]
acot(x)*acos(x) acot(x)
--------------- + ------- = tan(x)
5 45
$$\frac{\operatorname{acos}{\left(x \right)} \operatorname{acot}{\left(x \right)}}{5} + \frac{\operatorname{acot}{\left(x \right)}}{45} = \tan{\left(x \right)}$$
Respuesta numérica
[src]
x1 = -53.4192593233813 + 0.017482097756084*i
x2 = -87.9719909971704 + 0.0117524482151625*i
x3 = -75.4068534485045 + 0.0133013265862547*i
x4 = -81.6893747883885 + 0.0124746295109792*i
x5 = -78.548100836617 + 0.0128734975136915*i
x6 = -6.38505093122818 - 0.0770966793028596*i
x7 = -37.7163740620542 + 0.0229054195420113*i
x8 = -22.0207358342007 + 0.0342870913014007*i
x9 = -65.9833086187846 + 0.0147954686488648*i
x10 = -43.9970929395843 + 0.0203400032563534*i
x11 = -40.8566386552825 + 0.0215389078428113*i
x12 = -59.7011617791431 + 0.0160162694383589*i
x13 = -84.8306723519564 + 0.0121017934960751*i
x14 = -12.6180464400305 + 0.0507393316344634*i
x15 = -47.1376989956057 + 0.0192788043697885*i
x16 = -50.2784283761695 + 0.0183322147495479*i
x17 = 0.326570141614281
x18 = -28.2973499184866 + 0.0284804631197869*i
x19 = -34.5763508484023 + 0.0244789876677196*i
x20 = -69.1244528542811 + 0.0142580105450027*i
x21 = -9.49345606990475 + 0.0610811216011037*i
x22 = -56.5601749121189 + 0.0167140033108669*i
x23 = -62.8422092331293 + 0.0153793755559085*i
x24 = -15.7493540169392 + 0.0435780985551165*i
x25 = -53.4192593233813 - 0.017482097756084*i
x26 = -97.3960530185351 + 0.0108245256851212*i
x27 = -91.1133285428864 + 0.0114243775593781*i
x28 = -18.8840661350892 + 0.0383206762208851*i
x29 = -94.2546830987997 + 0.0111156397263811*i
x30 = -31.436641338725 + 0.0263128072711898*i
x31 = -97.3960530185351 - 0.0108245256851212*i
x32 = -25.1586329800694 + 0.0310868648464685*i
x33 = -31.436641338725 - 0.0263128072711898*i
x34 = -6.38505093122818 + 0.0770966793028596*i
x35 = -75.4068534485045 - 0.0133013265862547*i
x36 = -72.2656360892956 + 0.0137615115385881*i
x37 = -3.33205317611908 + 0.100495461469205*i
x38 = -100.537436861532 + 0.0105495250086503*i
x38 = -100.537436861532 + 0.0105495250086503*i