log(c^1*x)=-log(log(y/x)+1) la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Suma y producto de raíces
[src]
/ 1 \ / 1 \
| -1 + ---| | -1 + ---|
| c*x| | c*x|
I*im\x*e / + re\x*e /
$$\operatorname{re}{\left(x e^{-1 + \frac{1}{c x}}\right)} + i \operatorname{im}{\left(x e^{-1 + \frac{1}{c x}}\right)}$$
/ 1 \ / 1 \
| -1 + ---| | -1 + ---|
| c*x| | c*x|
I*im\x*e / + re\x*e /
$$\operatorname{re}{\left(x e^{-1 + \frac{1}{c x}}\right)} + i \operatorname{im}{\left(x e^{-1 + \frac{1}{c x}}\right)}$$
/ 1 \ / 1 \
| -1 + ---| | -1 + ---|
| c*x| | c*x|
I*im\x*e / + re\x*e /
$$\operatorname{re}{\left(x e^{-1 + \frac{1}{c x}}\right)} + i \operatorname{im}{\left(x e^{-1 + \frac{1}{c x}}\right)}$$
/ / 1 \ / 1 \\
| | ---| | ---||
| | c*x| | c*x|| -1
\I*im\x*e / + re\x*e //*e
$$\frac{\operatorname{re}{\left(x e^{\frac{1}{c x}}\right)} + i \operatorname{im}{\left(x e^{\frac{1}{c x}}\right)}}{e}$$
(i*im(x*exp(1/(c*x))) + re(x*exp(1/(c*x))))*exp(-1)
/ 1 \ / 1 \
| -1 + ---| | -1 + ---|
| c*x| | c*x|
y1 = I*im\x*e / + re\x*e /
$$y_{1} = \operatorname{re}{\left(x e^{-1 + \frac{1}{c x}}\right)} + i \operatorname{im}{\left(x e^{-1 + \frac{1}{c x}}\right)}$$
y1 = re(x*exp(-1 + 1/(c*x))) + i*im(x*exp(-1 + 1/(c*x)))