ln(y)-1=(y/3)+(2/3) la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
/ / 5/3 \\ / / 5/3 \\
| |-e || | |-e ||
y1 = - 3*re|W|------|| - 3*I*im|W|------||
\ \ 3 // \ \ 3 //
$$y_{1} = - 3 \operatorname{re}{\left(W\left(- \frac{e^{\frac{5}{3}}}{3}\right)\right)} - 3 i \operatorname{im}{\left(W\left(- \frac{e^{\frac{5}{3}}}{3}\right)\right)}$$
y1 = -3*re(LambertW(-exp(5/3)/3)) - 3*i*im(LambertW(-exp(5/3)/3))
Suma y producto de raíces
[src]
/ / 5/3 \\ / / 5/3 \\
| |-e || | |-e ||
- 3*re|W|------|| - 3*I*im|W|------||
\ \ 3 // \ \ 3 //
$$- 3 \operatorname{re}{\left(W\left(- \frac{e^{\frac{5}{3}}}{3}\right)\right)} - 3 i \operatorname{im}{\left(W\left(- \frac{e^{\frac{5}{3}}}{3}\right)\right)}$$
/ / 5/3 \\ / / 5/3 \\
| |-e || | |-e ||
- 3*re|W|------|| - 3*I*im|W|------||
\ \ 3 // \ \ 3 //
$$- 3 \operatorname{re}{\left(W\left(- \frac{e^{\frac{5}{3}}}{3}\right)\right)} - 3 i \operatorname{im}{\left(W\left(- \frac{e^{\frac{5}{3}}}{3}\right)\right)}$$
/ / 5/3 \\ / / 5/3 \\
| |-e || | |-e ||
- 3*re|W|------|| - 3*I*im|W|------||
\ \ 3 // \ \ 3 //
$$- 3 \operatorname{re}{\left(W\left(- \frac{e^{\frac{5}{3}}}{3}\right)\right)} - 3 i \operatorname{im}{\left(W\left(- \frac{e^{\frac{5}{3}}}{3}\right)\right)}$$
/ / 5/3 \\ / / 5/3 \\
| |-e || | |-e ||
- 3*re|W|------|| - 3*I*im|W|------||
\ \ 3 // \ \ 3 //
$$- 3 \operatorname{re}{\left(W\left(- \frac{e^{\frac{5}{3}}}{3}\right)\right)} - 3 i \operatorname{im}{\left(W\left(- \frac{e^{\frac{5}{3}}}{3}\right)\right)}$$
-3*re(LambertW(-exp(5/3)/3)) - 3*i*im(LambertW(-exp(5/3)/3))
y1 = -0.249284763813781 + 4.86594617752164*i
y1 = -0.249284763813781 + 4.86594617752164*i