ctg(y)=x la ecuación
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Solución
Solución detallada
Tenemos la ecuación
cot(y)=xcambiamos
−x+cot(y)−1=0−x+cot(y)−1=0Sustituimos
w=cot(y)Transportamos los términos libres (sin w)
del miembro izquierdo al derecho, obtenemos:
w−x=1Move the summands with the other variables
del miembro izquierdo al derecho, obtenemos:
w=x+1Obtenemos la respuesta: w = 1 + x
hacemos cambio inverso
cot(y)=wsustituimos w:
sin(2*re(y)) I*sinh(2*im(y))
x1 = - ----------------------------- - -----------------------------
-cosh(2*im(y)) + cos(2*re(y)) -cosh(2*im(y)) + cos(2*re(y))
x1=−cos(2re(y))−cosh(2im(y))sin(2re(y))−cos(2re(y))−cosh(2im(y))isinh(2im(y))
x1 = -sin(2*re(y))/(cos(2*re(y)) - cosh(2*im(y))) - i*sinh(2*im(y))/(cos(2*re(y)) - cosh(2*im(y)))
Suma y producto de raíces
[src]
sin(2*re(y)) I*sinh(2*im(y))
- ----------------------------- - -----------------------------
-cosh(2*im(y)) + cos(2*re(y)) -cosh(2*im(y)) + cos(2*re(y))
−cos(2re(y))−cosh(2im(y))sin(2re(y))−cos(2re(y))−cosh(2im(y))isinh(2im(y))
sin(2*re(y)) I*sinh(2*im(y))
- ----------------------------- - -----------------------------
-cosh(2*im(y)) + cos(2*re(y)) -cosh(2*im(y)) + cos(2*re(y))
−cos(2re(y))−cosh(2im(y))sin(2re(y))−cos(2re(y))−cosh(2im(y))isinh(2im(y))
sin(2*re(y)) I*sinh(2*im(y))
- ----------------------------- - -----------------------------
-cosh(2*im(y)) + cos(2*re(y)) -cosh(2*im(y)) + cos(2*re(y))
−cos(2re(y))−cosh(2im(y))sin(2re(y))−cos(2re(y))−cosh(2im(y))isinh(2im(y))
-(I*sinh(2*im(y)) + sin(2*re(y)))
----------------------------------
-cosh(2*im(y)) + cos(2*re(y))
−cos(2re(y))−cosh(2im(y))sin(2re(y))+isinh(2im(y))
-(i*sinh(2*im(y)) + sin(2*re(y)))/(-cosh(2*im(y)) + cos(2*re(y)))