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- La ecuación:
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Ecuación x=(x+1)/2
- Ecuación (x-6)(-5x-9)=0
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Ecuación x^2-14*x+33=0
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Ecuación 5-x^2=0
- Expresar {x} en función de y en la ecuación:
- 12*x+1*y=15
- -17*x-12*y=-9
- 18*x+17*y=-14
- 14*x-10*y=-4
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Expresiones idénticas
- log(cuatro ^x-b, dos)= cero
- logaritmo de (4 en el grado x menos b,2) es igual a 0
- logaritmo de (cuatro en el grado x menos b, dos) es igual a cero
- log(4x-b,2)=0
- log4x-b,2=0
- log4^x-b,2=0
- log(4^x-b,2)=O
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Expresiones semejantes
- log(4^x+b,2)=0
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Expresiones con funciones
- Logaritmo log
- log^24x−log4x^3+2=0
- log(4)(x^2+14(x)+50)/log(4)(x+10)=1
- log(1/6)*(x-5)=x+1
- log(2*x-1)+log(x-9)=2
- logax=0
log(4^x-b,2)=0 la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Ha introducido
[src]
/ x \ log\4 - b/ ----------- = 0 log(2)
$$\frac{\log{\left(4^{x} - b \right)}}{\log{\left(2 \right)}} = 0$$
Gráfica
Respuesta rápida
[src]
/| _______|\ / _______\
log\|\/ 1 + b |/ I*arg\-\/ 1 + b /
x1 = ---------------- + -----------------
log(2) log(2)
$$x_{1} = \frac{\log{\left(\left|{\sqrt{b + 1}}\right| \right)}}{\log{\left(2 \right)}} + \frac{i \arg{\left(- \sqrt{b + 1} \right)}}{\log{\left(2 \right)}}$$
log(|1 + b|) I*arg(1 + b)
x2 = ------------ + ------------
2*log(2) 2*log(2)
$$x_{2} = \frac{\log{\left(\left|{b + 1}\right| \right)}}{2 \log{\left(2 \right)}} + \frac{i \arg{\left(b + 1 \right)}}{2 \log{\left(2 \right)}}$$
x2 = log(|b + 1|)/(2*log(2)) + i*arg(b + 1)/(2*log(2))
Suma y producto de raíces
[src]
suma
/| _______|\ / _______\
log\|\/ 1 + b |/ I*arg\-\/ 1 + b / log(|1 + b|) I*arg(1 + b)
---------------- + ----------------- + ------------ + ------------
log(2) log(2) 2*log(2) 2*log(2)
$$\left(\frac{\log{\left(\left|{\sqrt{b + 1}}\right| \right)}}{\log{\left(2 \right)}} + \frac{i \arg{\left(- \sqrt{b + 1} \right)}}{\log{\left(2 \right)}}\right) + \left(\frac{\log{\left(\left|{b + 1}\right| \right)}}{2 \log{\left(2 \right)}} + \frac{i \arg{\left(b + 1 \right)}}{2 \log{\left(2 \right)}}\right)$$
=
/| _______|\ / _______\
log\|\/ 1 + b |/ log(|1 + b|) I*arg\-\/ 1 + b / I*arg(1 + b)
---------------- + ------------ + ----------------- + ------------
log(2) 2*log(2) log(2) 2*log(2)
$$\frac{\log{\left(\left|{\sqrt{b + 1}}\right| \right)}}{\log{\left(2 \right)}} + \frac{\log{\left(\left|{b + 1}\right| \right)}}{2 \log{\left(2 \right)}} + \frac{i \arg{\left(- \sqrt{b + 1} \right)}}{\log{\left(2 \right)}} + \frac{i \arg{\left(b + 1 \right)}}{2 \log{\left(2 \right)}}$$
producto
/ /| _______|\ / _______\\ |log\|\/ 1 + b |/ I*arg\-\/ 1 + b /| /log(|1 + b|) I*arg(1 + b)\ |---------------- + -----------------|*|------------ + ------------| \ log(2) log(2) / \ 2*log(2) 2*log(2) /
$$\left(\frac{\log{\left(\left|{\sqrt{b + 1}}\right| \right)}}{\log{\left(2 \right)}} + \frac{i \arg{\left(- \sqrt{b + 1} \right)}}{\log{\left(2 \right)}}\right) \left(\frac{\log{\left(\left|{b + 1}\right| \right)}}{2 \log{\left(2 \right)}} + \frac{i \arg{\left(b + 1 \right)}}{2 \log{\left(2 \right)}}\right)$$
=
/ / _______\ /| _______|\\
\I*arg\-\/ 1 + b / + log\|\/ 1 + b |//*(I*arg(1 + b) + log(|1 + b|))
--------------------------------------------------------------------
2
2*log (2)
$$\frac{\left(\log{\left(\left|{\sqrt{b + 1}}\right| \right)} + i \arg{\left(- \sqrt{b + 1} \right)}\right) \left(\log{\left(\left|{b + 1}\right| \right)} + i \arg{\left(b + 1 \right)}\right)}{2 \log{\left(2 \right)}^{2}}$$
(i*arg(-sqrt(1 + b)) + log(Abs(sqrt(1 + b))))*(i*arg(1 + b) + log(|1 + b|))/(2*log(2)^2)