1+(5a-3)/(x-a)=5(2a+1)(1-a)/((x-a)(x-3a+1)) la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Suma y producto de raíces
[src]
4 - 2*re(a) - 2*I*im(a) + -2 + I*im(a) + re(a)
$$\left(- 2 \operatorname{re}{\left(a\right)} - 2 i \operatorname{im}{\left(a\right)} + 4\right) + \left(\operatorname{re}{\left(a\right)} + i \operatorname{im}{\left(a\right)} - 2\right)$$
$$- \operatorname{re}{\left(a\right)} - i \operatorname{im}{\left(a\right)} + 2$$
(4 - 2*re(a) - 2*I*im(a))*(-2 + I*im(a) + re(a))
$$\left(- 2 \operatorname{re}{\left(a\right)} - 2 i \operatorname{im}{\left(a\right)} + 4\right) \left(\operatorname{re}{\left(a\right)} + i \operatorname{im}{\left(a\right)} - 2\right)$$
2
-2*(-2 + I*im(a) + re(a))
$$- 2 \left(\operatorname{re}{\left(a\right)} + i \operatorname{im}{\left(a\right)} - 2\right)^{2}$$
-2*(-2 + i*im(a) + re(a))^2
x1 = 4 - 2*re(a) - 2*I*im(a)
$$x_{1} = - 2 \operatorname{re}{\left(a\right)} - 2 i \operatorname{im}{\left(a\right)} + 4$$
x2 = -2 + I*im(a) + re(a)
$$x_{2} = \operatorname{re}{\left(a\right)} + i \operatorname{im}{\left(a\right)} - 2$$