Resolución de la ecuación paramétrica
Se da la ecuación con parámetro:
$$f z = 2 - z$$
Коэффициент при z равен
$$f + 1$$
entonces son posibles los casos para f :
$$f < -1$$
$$f = -1$$
Consideremos todos los casos con detalles:
Con
$$f < -1$$
la ecuación será
$$- z - 2 = 0$$
su solución
$$z = -2$$
Con
$$f = -1$$
la ecuación será
$$-2 = 0$$
su solución
no hay soluciones
2*(1 + re(f)) 2*I*im(f)
z1 = --------------------- - ---------------------
2 2 2 2
(1 + re(f)) + im (f) (1 + re(f)) + im (f)
$$z_{1} = \frac{2 \left(\operatorname{re}{\left(f\right)} + 1\right)}{\left(\operatorname{re}{\left(f\right)} + 1\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} - \frac{2 i \operatorname{im}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)} + 1\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}}$$
z1 = 2*(re(f) + 1)/((re(f) + 1)^2 + im(f)^2) - 2*i*im(f)/((re(f) + 1)^2 + im(f)^2)
Suma y producto de raíces
[src]
2*(1 + re(f)) 2*I*im(f)
--------------------- - ---------------------
2 2 2 2
(1 + re(f)) + im (f) (1 + re(f)) + im (f)
$$\frac{2 \left(\operatorname{re}{\left(f\right)} + 1\right)}{\left(\operatorname{re}{\left(f\right)} + 1\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} - \frac{2 i \operatorname{im}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)} + 1\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}}$$
2*(1 + re(f)) 2*I*im(f)
--------------------- - ---------------------
2 2 2 2
(1 + re(f)) + im (f) (1 + re(f)) + im (f)
$$\frac{2 \left(\operatorname{re}{\left(f\right)} + 1\right)}{\left(\operatorname{re}{\left(f\right)} + 1\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} - \frac{2 i \operatorname{im}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)} + 1\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}}$$
2*(1 + re(f)) 2*I*im(f)
--------------------- - ---------------------
2 2 2 2
(1 + re(f)) + im (f) (1 + re(f)) + im (f)
$$\frac{2 \left(\operatorname{re}{\left(f\right)} + 1\right)}{\left(\operatorname{re}{\left(f\right)} + 1\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} - \frac{2 i \operatorname{im}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)} + 1\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}}$$
2*(1 - I*im(f) + re(f))
-----------------------
2 2
(1 + re(f)) + im (f)
$$\frac{2 \left(\operatorname{re}{\left(f\right)} - i \operatorname{im}{\left(f\right)} + 1\right)}{\left(\operatorname{re}{\left(f\right)} + 1\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}}$$
2*(1 - i*im(f) + re(f))/((1 + re(f))^2 + im(f)^2)