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Gráfico de la función y = log(1+x*e^x)/log(x+sqrt(1+x^2))

v

Gráfico:

interior superior

Puntos de intersección:

mostrar?

Definida a trozos:

Solución

Ha introducido [src]
             /       x\    
          log\1 + x*E /    
f(x) = --------------------
          /       ________\
          |      /      2 |
       log\x + \/  1 + x  /
f(x)=log(exx+1)log(x+x2+1)f{\left(x \right)} = \frac{\log{\left(e^{x} x + 1 \right)}}{\log{\left(x + \sqrt{x^{2} + 1} \right)}}
f = log(E^x*x + 1)/log(x + sqrt(x^2 + 1))
Gráfico de la función
02468-8-6-4-2-101005
Dominio de definición de la función
Puntos en los que la función no está definida exactamente:
x1=0x_{1} = 0
Puntos de cruce con el eje de coordenadas X
El gráfico de la función cruce el eje X con f = 0
o sea hay que resolver la ecuación:
log(exx+1)log(x+x2+1)=0\frac{\log{\left(e^{x} x + 1 \right)}}{\log{\left(x + \sqrt{x^{2} + 1} \right)}} = 0
Resolvermos esta ecuación
Puntos de cruce con el eje X:

Solución numérica
x1=43.3994514654678x_{1} = -43.3994514654678
x2=33.7002291278265x_{2} = -33.7002291278265
x3=45.7597410257952x_{3} = -45.7597410257952
x4=84x_{4} = -84
x5=51.2941476996224x_{5} = -51.2941476996224
x6=68x_{6} = -68
x7=90x_{7} = -90
x8=46.53087513762x_{8} = -46.53087513762
x9=38.3836333251876x_{9} = -38.3836333251876
x10=45.3713261043746x_{10} = -45.3713261043746
x11=45.3682799020102x_{11} = -45.3682799020102
x12=98x_{12} = -98
x13=37.0441473368719x_{13} = -37.0441473368719
x14=44.5884552810949x_{14} = -44.5884552810949
x15=40.1081793647041x_{15} = -40.1081793647041
x16=48.8029498623465x_{16} = -48.8029498623465
x17=37.4956282276754x_{17} = -37.4956282276754
x18=32.6632900979411x_{18} = -32.6632900979411
x19=39.2537917748258x_{19} = -39.2537917748258
x20=35.1786456692558x_{20} = -35.1786456692558
x21=387.445030565266x_{21} = -387.445030565266
x22=34.6946355029704x_{22} = -34.6946355029704
x23=35.6549717870873x_{23} = -35.6549717870873
x24=47.2948294456441x_{24} = -47.2948294456441
x25=65.2185316851804x_{25} = -65.2185316851804
x26=92x_{26} = -92
x27=42.592245598174x_{27} = -42.592245598174
x28=39.4760749477738x_{28} = -39.4760749477738
x29=86x_{29} = -86
x30=67.485973353229x_{30} = -67.485973353229
x31=49.3161717843167x_{31} = -49.3161717843167
x32=42.1855534362529x_{32} = -42.1855534362529
x33=100x_{33} = -100
x34=36.1242900447651x_{34} = -36.1242900447651
x35=59.2246697567999x_{35} = -59.2246697567999
x36=33.1877436645797x_{36} = -33.1877436645797
x37=41.3638095051796x_{37} = -41.3638095051796
x38=76x_{38} = -76
x39=42.9963140722135x_{39} = -42.9963140722135
x40=68.0275704279569x_{40} = -68.0275704279569
x41=47.3407233500386x_{41} = -47.3407233500386
x42=48.4282673214477x_{42} = -48.4282673214477
x43=37.5240176245332x_{43} = -37.5240176245332
x44=78x_{44} = -78
x45=31.7343085974711x_{45} = -31.7343085974711
x46=48.0520533355827x_{46} = -48.0520533355827
x47=34.2021456592464x_{47} = -34.2021456592464
x48=57.2397727579464x_{48} = -57.2397727579464
x49=41.4350316533908x_{49} = -41.4350316533908
x50=67.528274142588x_{50} = -67.528274142588
x51=39.6828434480538x_{51} = -39.6828434480538
x52=36.5871809504796x_{52} = -36.5871809504796
x53=30.4023040253644x_{53} = -30.4023040253644
x54=63.1970847942379x_{54} = -63.1970847942379
x55=30.9980586467113x_{55} = -30.9980586467113
x56=392.30577478002x_{56} = -392.30577478002
x57=82x_{57} = -82
x58=38.820803308266x_{58} = -38.820803308266
x59=33.6495469060591x_{59} = -33.6495469060591
x60=31.5710171171308x_{60} = -31.5710171171308
x61=88x_{61} = -88
x62=393.262799640241x_{62} = -393.262799640241
x63=29.7781851770083x_{63} = -29.7781851770083
x64=41.7761179000335x_{64} = -41.7761179000335
x65=32.1251230266095x_{65} = -32.1251230266095
x66=46.9137204075844x_{66} = -46.9137204075844
x67=72x_{67} = -72
x68=40.5299999850927x_{68} = -40.5299999850927
x69=46.146235748999x_{69} = -46.146235748999
x70=55.2562382064487x_{70} = -55.2562382064487
x71=66.8449972607667x_{71} = -66.8449972607667
x72=74x_{72} = -74
x73=61.2124560959278x_{73} = -61.2124560959278
x74=35.5808727505208x_{74} = -35.5808727505208
x75=391.113901380411x_{75} = -391.113901380411
x76=67.3375706608183x_{76} = -67.3375706608183
x77=37.9420096728669x_{77} = -37.9420096728669
x78=53.2742716967352x_{78} = -53.2742716967352
x79=393.431988661188x_{79} = -393.431988661188
x80=43.3978697635907x_{80} = -43.3978697635907
x81=43.7970156806803x_{81} = -43.7970156806803
x82=47.6742561836685x_{82} = -47.6742561836685
x83=387.356894030113x_{83} = -387.356894030113
x84=29.8411235040176x_{84} = -29.8411235040176
x85=44.9809219917996x_{85} = -44.9809219917996
x86=44.1938477072055x_{86} = -44.1938477072055
x87=40.9484877961702x_{87} = -40.9484877961702
x88=70x_{88} = -70
x89=96x_{89} = -96
x90=80x_{90} = -80
x91=94x_{91} = -94
Puntos de cruce con el eje de coordenadas Y
El gráfico cruce el eje Y cuando x es igual a 0:
sustituimos x = 0 en log(1 + x*E^x)/log(x + sqrt(1 + x^2)).
log(0e0+1)log(02+1)\frac{\log{\left(0 e^{0} + 1 \right)}}{\log{\left(\sqrt{0^{2} + 1} \right)}}
Resultado:
f(0)=NaNf{\left(0 \right)} = \text{NaN}
- no hay soluciones de la ecuación
Asíntotas verticales
Hay:
x1=0x_{1} = 0
Asíntotas horizontales
Hallemos las asíntotas horizontales mediante los límites de esta función con x->+oo y x->-oo
limx(log(exx+1)log(x+x2+1))=0\lim_{x \to -\infty}\left(\frac{\log{\left(e^{x} x + 1 \right)}}{\log{\left(x + \sqrt{x^{2} + 1} \right)}}\right) = 0
Tomamos como el límite
es decir,
ecuación de la asíntota horizontal a la izquierda:
y=0y = 0
limx(log(exx+1)log(x+x2+1))=\lim_{x \to \infty}\left(\frac{\log{\left(e^{x} x + 1 \right)}}{\log{\left(x + \sqrt{x^{2} + 1} \right)}}\right) = \infty
Tomamos como el límite
es decir,
no hay asíntota horizontal a la derecha
Asíntotas inclinadas
Se puede hallar la asíntota inclinada calculando el límite de la función log(1 + x*E^x)/log(x + sqrt(1 + x^2)), dividida por x con x->+oo y x ->-oo
limx(log(exx+1)xlog(x+x2+1))=0\lim_{x \to -\infty}\left(\frac{\log{\left(e^{x} x + 1 \right)}}{x \log{\left(x + \sqrt{x^{2} + 1} \right)}}\right) = 0
Tomamos como el límite
es decir,
la inclinada coincide con la asíntota horizontal a la derecha
limx(log(exx+1)xlog(x+x2+1))=0\lim_{x \to \infty}\left(\frac{\log{\left(e^{x} x + 1 \right)}}{x \log{\left(x + \sqrt{x^{2} + 1} \right)}}\right) = 0
Tomamos como el límite
es decir,
la inclinada coincide con la asíntota horizontal a la izquierda
Paridad e imparidad de la función
Comprobemos si la función es par o impar mediante las relaciones f = f(-x) и f = -f(-x).
Pues, comprobamos:
log(exx+1)log(x+x2+1)=log(xex+1)log(x+x2+1)\frac{\log{\left(e^{x} x + 1 \right)}}{\log{\left(x + \sqrt{x^{2} + 1} \right)}} = \frac{\log{\left(- x e^{- x} + 1 \right)}}{\log{\left(- x + \sqrt{x^{2} + 1} \right)}}
- No
log(exx+1)log(x+x2+1)=log(xex+1)log(x+x2+1)\frac{\log{\left(e^{x} x + 1 \right)}}{\log{\left(x + \sqrt{x^{2} + 1} \right)}} = - \frac{\log{\left(- x e^{- x} + 1 \right)}}{\log{\left(- x + \sqrt{x^{2} + 1} \right)}}
- No
es decir, función
no es
par ni impar